If the kinetic energy formula is the same as Einstein's formula then $E=mc^2=\dfrac{1}{2} mv^2$. Or, $\dfrac{1}{2}v^2=c^2$. What does this prove? Does it prove that $\dfrac{1}{2}$ of the velocity squared of a moving object is always equal to speed of light squared?
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I think I have the answer.
Energy= mc2+ 1/2 mv2. Both the formulas arent equal but to get total energy we need to add both. Sorry guys my mistake. Any more insights to this? Maybe you can explain why add both these formulas.
avito009
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"This is an equation that takes into account both the kinetic energy and the mass increase due to motion, at least for low speeds. But how?"
Energy and mass are equal. So when we move an object very slow the v2 in the formula 1/2 mv2 is low so Energy is equal to this mass which is 1/2m*v2. this accounts for mass increase. Got it?
This 1/2m*v2 is nothing but the mass after moving. Since E=M (Energy equals mass).
avito009
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