How would a magnet fall through a copper ring with a cut in it, so as to not form a complete loop?

Question

The magnet is slowed down when it falls through the complete loop, but since the cut makes the ring incomplete, I'm inclined to think that there will be no induced current in the ring and thus the magnet falls with no change in acceleration.

Answer 1

there is an induced current but it is smaller than for an unslotted tube. The induced current consists of eddy current rings which all add up to make a current loop along the interior walls of the copper