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In both statistical field theory and quantum field theory one computes average values / time ordered expectation values of functionals of fields with the path integral. I have two related questions:

  1. Is it the path integral alone that make quantum fields non-commutative or are other constraints also required?

  2. Are statistical fields non-commutative?

Qmechanic
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Luke
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1 Answers1

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1) It's exactly the opposite of what you said - in the Hamiltonian operator formalism, the fields are non-commutative; the Lagrangian path integral is an equivalent reformulation of the problem in which the fields are commutative. Field ordering doesn't matter in the path integral; the original "non-commuting-ness" effectively gets absorbed into the integration measure.

2) I guess it depends on exactly what you mean by "statistical fields," but nope, anything that goes into a path integral is commutative.

tparker
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