0

Can we annihilate a photon with an opposite phase? As two photons annihilate to give two antimatter photons (with opposite charge), these photons must have some opposite property. When these opposite photons annihilate, what happens?

Also, why there is no black light? I think that there must be a black light made of antiphotons, and in a black hole, antiphotons exist, causing the black hole to be black.

auden
  • 7,085

1 Answers1

-1

Perhaps I'm misunderstanding your statement, but in order to 'annihilate' two photons you must have a reaction between an equivalent quantity of antiphotons, which are essentially photons with different charges and leptons, which i link to spin, which I assume is phase. When they annihilate, they theoretically combine in such a way as to negate their existence through subatomic congruency, which is pretty incredible. A flash of energy and then conjecture takes over. Light is simply a perception, the energy contained in light stimulates (overcomes gateway thresholds) within the eye. Blackness by definition is the lack of light. Also, within a black hole it's not that there is an absence of light, we just perceive it that way because the force exerted on the photons prevents that energy from ever reaching our eyes. You could be right, it's theory, but there's also a theory based on some interesting and sound research that points towards a heliocentric universe after all. Boom