I have a perfectly insulated container with $N$ molecules of air at an initial temperature $T_{0}$ and pressure $P_{0}$. Imagine that I now have a set of thermodynamic 'tweezers' that allows me to remove individual molecules from the container (i.e. i'm trying to mimic a vacuum pump type of device). How do I work out how my pressure and temperature will change as I remove molecules from the container?
Attempt:
$dU = dW + dQ + \mu dN$
Am I allowed to say that $dW=0$ since $dW = - P dV$ and since $dV=0$, then $dW=0$?
Also, can I say that $dQ = 0$ since it's perfectly isolated? I would initially think no because as I remove molecules from the container, I'm also removing some heat as I do this, correct? Or is this completely accounted from in the thermodynamic chemical potential/Fermi energy $\mu$ - i.e. the energy added to system for every one molecule added (if that's the correct definition).
I'm just a bit rusty on my thermodynamics. I feel like I'm also not given proper consideration to the fact that the processes are irreversible.
Any help/guidance is appreciated.
BTW if $dW=0$ and $dQ=0$, then the solution I get is something like:
$\Delta T = \frac{-\Delta N (T - (\mu/1.5k_{B}) )}{N + \Delta N}$
after integrating, etc...
this basically says as I remove molecules, my temperature of the system will go up. But I thought creating a vacuum should make the temperature go now (like in space)