Suppose I have a 2-form field $B$ and a Lagrange multiplier field $\lambda$, then the Lagrangian
$S = \int (B \wedge \delta B + \lambda \delta B \wedge \delta B)$
with a Lie derivative operator $\delta$ (doesn't change the differential form) generates a probability for scattering with the fields $B$ (see also: http://thewinnower.com/papers/2658-topological-dipole-field-theory).
Now suppose I have (EXAMPLE ONLY!) to compute the expectation value (integral measure does also contain the normalization factors):
$<B_{\alpha_1 \beta_1}(x_1)B_{\alpha_2 \beta_2}(x_2)B_{\alpha_3 \beta_3}(x_3)B_{\alpha_4 \beta_4}(x_4)>= \int d[B] \times \int d[\lambda] B_{\alpha_1 \beta_1}(x_1)B_{\alpha_2 \beta_2}(x_2)B_{\alpha_3 \beta_3}(x_3)B_{\alpha_4 \beta_4}(x_4)e^{iS}$.
In k-space I can write for the action $S = (2 \pi)^4\int d^4k \epsilon_{\alpha \beta \mu \nu}B_k^{\alpha \beta}\delta_k B_k^{\mu \nu} + (2 \pi)^4 \int \int d^4k d^4k' \lambda_{k'-k}\epsilon_{\alpha \beta \mu \nu}\delta_{k'}B_{k'}^{\alpha \beta}\delta_k B_k^{\mu \nu}$.
My question is the following: Since $\lambda(x)$ is a Lagrange multiplier field one has a scattering term of the action given by $S_{sc} = (2 \pi)^4 \int \int d^4k d^4k' \lambda_{k'-k}\epsilon_{\alpha \beta \mu \nu}\delta_{k'}B_{k'}^{\alpha \beta}\delta_k B_k^{\mu \nu}$. The other term is the kinetic term (Generalized gaussian integral).
Expanding the scattering term in Taylor series one obtains the elementary scattering processes: $B_{k'}^{\alpha \beta} \mapsto B_{k'}^{\mu \nu}$. There was transferred an excess of energy-momentum $\lambda_{k-k'}$. Has the constraint generated a nonconservation of energy and momentum?
If one knows it (this must not be answered necessarily): Loop quantum gravity is a QFT with constraints. Is in Loop quantum gravity energy and momentum conserved?
Every reply would be greatly appreciated.