I have a container (assume open on top) with $1m^3$ of water. That water exits this container from an opening that has a cross-section area A e.g. $πR^2$ = $1cm^2$.
What is the volumetric flow rate I get out of this opening? I have a feeling that it's related to $R^4$ due to Hagen–Poiseuille equation but on the other hand it has the $|DP|$ that might also be related to R in some way. Is there any way to force the volumetric flow rate to be ~$R^2$ (e.g. adjusting the pressure with a mechanical way?)
