Is it possible to create a beam of light with frequency of 0?
So this would involve photon(s) that move forward without fluctuating with any frequency.
If yes, how could this be done?
Also, considering that such a beam would not have any known color (since our eyes recognize color based on the frequency of the light beam), would it be possible to create a sensor that senses that beam?
We can represent a monochromatic electromagnetic wave by one of its fields, the $\vec E$ or $\vec B$ field (or $\vec H$ in the case of the diagram further down). For example, we can write $$\vec E (\vec r, t) = \vec E_0 e^{i(\vec k \cdot \vec r - \omega t)}$$ where the relevant part for this question is $\omega$, the angular velocity. When the frequency of a wave approaches 0, the angular velocity also approaches zero ($\omega = 2\pi f$, so $\omega$ and $f$ only differ by a factor of $2\pi$).
For an electromagnetic wave, the wavenumber follows $k = \frac{2\pi}{\lambda}$. From this you can see that with increasing wavelength $\lambda$, $k$ approaches zero as well.
The exponent in the exponential function therefore tends to zero with decreasing frequency and increasing wavelength: $e^0 = 1$.
We are left with $$\vec E (\vec r, t) = \vec E_0$$ which is the equation for a static electric field $\vec E_0$ which does not vary in time or position.
We are able to detect such a field for example by probing it with a test charge or measuring a voltage between two points.
The same derivation can be done with the magnetic field $$\vec B = \vec B_0 e^{i(\vec k \cdot \vec r - \omega t)}$$ and yields the same result (static magnetic field).
As for the question about color, color is merely a definition for specific wavelengths in the visible region of the EM spectrum. Since we also don't assign a color to x-rays or microwaves, the concept of color also does not apply to such a wave.
It will help if your read the answer by Motl in a similar question Virtual photon description of B and E fields.
Is it possible to create a beam of light with frequency of 0?
It will not be light, as you approach 0, it will be a radio wave, i.e. it will be generated by an antenna. Think of starting with a very low frequency and keep on diminishing it to approach 0 . The electrons on the antenna will be moving so slowly on the antenna that what one will see is a static electric field and will have to wait a very long time to see any change.
So this would involve photon(s) that move forward without fluctuating with any frequency.
Now we are talking quantum mechanics and the link above is illuminating. In quantum mechanics photons can be virtual,
the wave function of a single photon has several components - much like the components of the Dirac field (or Dirac wave function) - and this wave function is pretty much isomorphic to the electromagnetic field, remembering the complexified values of E and B vectors at each point. The probability density that a photon is found at a particular point is proportional to the energy density (E2+B2)/2 at this point. But again, the interpretation of B,E for a single photon has to be changed.
So whether the field around an object is electric or magnetic or both is encoded in the "polarization" of the virtual photons.
And virtual photons need studying Feynman diagrams and quantum electrodynamics. At the level you are asking you should take it on trust that quantum electrodynamics blends with classical electrodynamics smoothly .
If yes, how could this be done?
It is already done wherever there are electrostatic fields and magneto-static fields, they are not called beams.
Also, considering that such a beam would not have any known color (since our eyes recognize color based on the frequency of the light beam), would it be possible to create a sensor that senses that beam?
Voltmeters measure electric fields and compasses display magnetic ones.
A photon with 0 frequency wouldn't interact with anything, so it is impossible to know if it exists.
When working with nonlinear crystals, you can generate 0 frequency. TWM or Three wave mixing allows you to generate a frequency that can be sum or subtraction of two other frequency: $$\omega_3=\omega_2-\omega_1$$ If $\omega_2=\omega_1$ we have $\omega_3=0$ and then we can generate 0 frequency. when this occurs we have a constant current.
