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In our physics class we were discussing about Coulomb's Law and equation for the electrostatic force between two points: $$F_{e}=\frac{Q_{1}Q_{2}}{4\pi \epsilon_0 r^2}$$

From the equation a query arose which is for what reason does the constant involve $4\pi$.

JamalS
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1 Answers1

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It's just a matter of rationalisation and mathematical convenience. $4\pi$ corresponds to the whole solid angle, which usually simplifies when you deal with Gauss' theorem. In other words, you can simply redefine a constant $k$ to be any multiple of another constant, $1/E_0$ in this case.

Phoenix87
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