Based on the area velocity relation:
$\frac{dA}{A}=(M^2-1)\frac{du}{u}$
For M > 1, in order to increase u, we must increase A. I'm wondering what the explanation is physically and why it is opposite to that in subsonic flow.
Based on the area velocity relation:
$\frac{dA}{A}=(M^2-1)\frac{du}{u}$
For M > 1, in order to increase u, we must increase A. I'm wondering what the explanation is physically and why it is opposite to that in subsonic flow.