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As we know the mass-energy equivalence relation $E=mc^2$ originally came from special relativity. And the binding energy is $\Delta mc^2$. How do we know that the extra mass coming from theoretical calculation is associated with the binding energy? What is special relativity inside the nucleus?

Tea is life
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2 Answers2

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The relationship between nuclear masses and mass differences and binding energies has been confirmed by many decades of careful nuclear spectroscopy.

It's possible to measure an atom's mass by purely mechanical means: you ionize the atoms, accelerate them to a known energy, and use a magnetic field to measure their momentum. This lets you come up with an independent measurement of the mass of any particular nucleus. There are other methods, too.

It's also possible to absolutely measure the energy released in a nuclear reaction, by capturing all of the decay products and measuring their energy.

Now you have two datasets: a set of masses, and a set of transition energies. There's a lot of complicated feedback that goes into connecting the one to the other, but the long and short of it is that the equivalence between mass difference and binding energy difference is an experimental result, consistent with the prediction of relativity.

rob
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Rob's explanation of how we know is bang on, but I wanted to address a part of your question that might point to a basic misunderstanding.

What is special relativity inside the nucleus?

Everything is always relativity. Everything. Always.

All those Newtonian equations like $T = \frac12 m v^2$ for the kinetic energy can be properly understood as approximations (to the correct relativistic expression) that apply in the limit of low relative velocity. Including the notion that binding two objects of masses $m_1$ and $m_2$ gives you a object of mass $m = m_1 + m_2$.

There is no magic point at which relativity suddenly begins applying: it always applies. It's just that the Newtonian math is often easier, so people talk about the point at which they can no longer tolerate the imprecision that comes with using Newtonian physics.

The reason we can't tolerate the Newtonian view in nuclear physics is that binding energies are a non-trivial fraction of the mass-energy of the constituents. It's not a big fraction, but we can get access to it and that factor of $c^2$ is huge.