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For Weyl semimetal, the effective Hamiltonian reads:

$$H=E_0 \mathbb{1} + v_0 \cdot \mathrm{q} \mathbb{1}+\sum_{i=1}^{3} \mathrm{v}_i \cdot \mathrm{q} \sigma_i$$

Why is the chirality given by $${\rm sgn}(\mathrm{v}_1 \cdot \mathrm{v}_2 \times \mathrm{v}_3)~?$$

Qmechanic
  • 220,844
qc2014
  • 541

0 Answers0