If you leave a ball weighing 10 kg at a height of 500 km above sea level (neglecting air friction).
How can calculate how long the ball hits the ground and what will be its speed?
I know that: On earth I can calculate the time taken to the object to fall by this equivalent:
x = x0 + v0t + (at^2)/2
x = 0
x0 = 500000
v0 = 0
a = -g = 10 m/s^2
0 = 500000 - 5t^2
t = 316.227sec
Also I know how to calculate the force between objects:
g = GMm/r^2
