I havean LED ceiling light with a S4523B chip for cycling.
Would it be OK to disable cycling by shorting pin 1 and 3?
I would like both outputs to be on when the PCB gets power.
UPDATE2 (input part of the circuit):
I havean LED ceiling light with a S4523B chip for cycling.
Would it be OK to disable cycling by shorting pin 1 and 3?
I would like both outputs to be on when the PCB gets power.
UPDATE2 (input part of the circuit):
From what little I can make out from the datasheet, the Bright Power S4523 contains switching logic that changes its state whenever power is removed and reapplied soon afterwards (i.e. presumably while it still has a DC supply active on its HV pin from the smoothing capacitor). This allows it to activate one or both of the LED drivers using their Vcc/OVP/CTL input pins.
Making both drivers work at the same time, all the time, is therefore a matter of figuring out the state of those input pins when they are on. It's either going to be a connection to GND, a connection to the HV DC line that's also fed to the chip or just left completely open circuit.
As removing the chip and connecting the control lines to GND didn't work, it seems likely that connecting the control lines to GND is what turns off the LED drivers - so it must be one of the other options.
Pin 1 and 3 then going to respective driver: https://m.elecfans.com/article/1402414.html – Pablo Aug 29 '23 at 19:57