0

I have a PNP transistor connected as follows. I know that there is voltage divider between Vdd and Vin.

What is the logic behind this configuration of PNP? What kind of state it tries to bias it into? UPDATE: enter image description here

lub2354
  • 373
  • 2
  • 6
  • Where did you find this circuit? It won't do anything useful; any voltage significantly less than Vdd on the input will just short out Vdd. – Hearth Apr 06 '23 at 14:33
  • The PNP is wrongly connected, and the circuit is not helpful in anything, besides testing the reverse Vbe breakdown voltage. I suggest reading again some basic text on bipolar transistors. – LuC Apr 06 '23 at 14:36
  • Hello , I had a mistake. The circuit is updated. – lub2354 Apr 06 '23 at 15:00
  • @lub2354 It still does the same thing I said in the first place, just with the transistor in forward active instead of reverse active mode. – Hearth Apr 06 '23 at 15:27
  • Where is the circuit output (where to connect the load)? – Circuit fantasist Apr 06 '23 at 15:51
  • Hello, I have built the circuit attached bellow.My goal is to switch it into saturated state. for forward active PNP we need the Emitter-base forward biased and base-collector reversed biased. (emitter)P-N(base) needs to be V_E>V_B to forward biased. (base)N-P(collector) reversed biased V_base>V_collector.

    I think its in active state.How do i improve my circuit co i could switch it between saturation and active? Thanks.

    https://pdf1.alldatasheet.com/datasheet-pdf/view/11478/ONSEMI/2N5087.html

    https://ibb.co/0DpWMFM

     – lub2354 Apr 07 '23 at 15:57

0 Answers0