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This may be a weird question but for a BJT, we have

enter image description here

\$I_S\$ is the reverse saturation current and \$I_C\$ is the collector current which flows through all three parts of the BJT.

Now my question is, \$I_S\$ should also flow through all three parts of the BJT, so can't we just add/subtract \$I_S\$ from \$I_C\$ via KCL? Is that where the -1 comes from?.

TimWescott
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AlfroJang80
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0 Answers0