In the above circuit I was asked to find the input capacitance at the gate of Q1, Cg1, using the Miller approximation, to determine the frequency of the pole formed at the amplifier input in terms of Rsig, use the Miller approximation to find the input capacitance of Q2, and hence determine the total capacitance Cg2 at the drain of Q1, finally to use Cg2 to obtain the frequency of the pole formed at the interface between the two stages. Below's my attempt. Unfortunately I got stuck trying to find the frequency of the pole formed at the interface between the two stages. I'd appreciate some help with that.
\$M_{in}=[1/(j\omega C_{gd})]/(1-K))\$, where \$K=-g_m r_o\$ for CS.
Hence, the frequency of the pole formed at the amplifier input in terms of Rsig:
\$f_p=1/(2\pi R_{sig}(M_{in}+C_{gs}))\$
I think the input capacitance of Q2 would be:
\$C_{g2}=C_{gs} + C_{db} + K/[(j \omega C_{gd})(K-1)]\$
The big question -- in order to obtain the frequency of the pole formed at the interface between the two stages, do I now simply multiply \$C_{g2}\$ by \$r_o\$ to determine the time constant?

