-1

In parallel RC circuit, what is the behavior of current of capacitor C1? What is the time constant?

enter image description here

Ricardo
  • 6,164
  • 20
  • 53
  • 89
tnt
  • 25
  • 1
  • 2

2 Answers2

2

In the circuit as drawn, I am assuming the voltage source and capacitor are ideal and the voltage source is producing an instantaneous step from 0 to 5 V. In this case, the model gives an infinite current (or a current impulse) into the capacitor at the time of the voltage step.

But that does not tell you much about what a real circuit would do. It just tells you you have created an unrealistic model.

A more realistic model would include series resistance in the voltage source and capacitor models, and a nonzero rise time for the voltage source's output step. Any one of these improvements in the model would result in a finite current into the capacitor.

The Photon
  • 129,671
  • 3
  • 164
  • 309
1

The governing equation for a capacitor: \begin{equation} I = C \frac{dV}{dt} \end{equation}

If the circuit has been at DC "forever", then no current flows through the capacitor because V never changes.

However, forever is a long time and you can't actually have this in the real world. So replace the source with some V(t) which has V(0) = 0. Now you have an equation which describes what I is vs. t.

helloworld922
  • 16,770
  • 10
  • 56
  • 88
  • ...also which doesn't transition "instantaneously" – vicatcu Nov 29 '14 at 19:46
  • My question is: It is initially 0 Volt, when 5 volts is applied, what is the current passes throu the capacitor? Is it infinity therotically? – tnt Nov 29 '14 at 19:49
  • @tnt to understand what "really" happens (in the brief period of time before "steady state") you have to model the circuit as a transmission line - look up "bounce diagrams" – vicatcu Nov 29 '14 at 19:56
  • http://electronics.stackexchange.com/questions/844/what-are-the-behaviors-of-capacitors-and-inductors-at-time-t-0 – vicatcu Nov 29 '14 at 20:00