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How does a Watt (1mW from a lasermodule) relate to Amps (20mA max current rating for collector of a phototransistor) ?

I want to know if the 1mW output from the laser is within or outside the range of what the phototransistor can deal with (20mA max) Laser is powered of a 5V circuit.

petervd81
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  • Doesn't that depend on how much laser light hits the phototransistor? 5V * 20mA = 0.1Watts – horta May 02 '14 at 17:38
  • You can externally limit the current to the phototransistor (for example with a resistor). 1mW is a lot of light if it's focused on the tiny die (often they're spec'd at 1mW/cm^2). – Spehro Pefhany May 02 '14 at 17:48
  • @SpehroPefhany, in my application area, 1 mW incident on a 50-um diameter photodetector (~2x10^(-3) cm^2) is not out of line. – The Photon May 02 '14 at 18:02

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When light strikes a semiconductor photodetector, each photon absorbed in the active region generates a free carrier pair (an electron and a hole). These carriers are swept out of the active region and form the photocurrent of the receiver. Some types of devices, like phototransistors and avalanche photodiodes, have an additional gain mechanism so that the initially generated photocurrent is multiplied by a gain factor.

The fraction of the incident photons that stimulate useful photocurrent is called the quantum efficiency, usually denoted as \$\eta\$.

The overall ratio of output current to incident optical power is the responsivity, R.

The responsivity can be expressed as

\$R=M\eta{}\dfrac{e}{h\nu}\$,

where M is the gain, e is the fundamental charge, \$h\nu\$ is the photon energy.

Now the relation between optical input power, \$P\$, and photodetector current is

\$I = RP\$.

For practical problems, you need to look at the datasheet of your phototransistor, which is likely to have a characteristic curve similar to this to indicate the responsivity:

enter image description here

The Photon
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