How do I pipe a newline separated list as arguments to another command?

Question

So I have a list of usernames such as:

user1
user2
user3

I want to apply id on each of them and get something like:

uid=100(user1) gid=5(g1) groups=5(g1),6(g6),7(g10)
.
.

How can I achieve this? Please note that the list is the output of another command say mycommand.

score 23 · Accepted Answer · answered Dec 18 '17 at 08:23

mycommand | xargs -L1 id

Example:

$ (echo root; echo nobody) | xargs -L1 id
uid=0(root) gid=0(root) groups=0(root)
uid=65534(nobody) gid=65534(nogroup) groups=65534(nogroup)

You can also loop over the input in bash:

mycommand | while read line
do
    id "$line"
done

xargs converts input to arguments of a command. The -L1 option tells xargs to use each line as a sole argument to an invocation of the command.

score 6 · Answer 2 · answered Dec 18 '17 at 11:31

With bash, you can capture the lines of output into an array:

mapfile -t lines < <(mycommand)

And then iterate over them

for line in "${lines[@]}"; do
    id "$line"
done

This is not as concise as xargs, but if you need the lines for more than one thing, it's pretty useful.

score 0 · Answer 3 · edited Jun 02 '21 at 16:11

tar -czf reloads.stage.tgz $(find . | egrep "sh$|functions$|sql$|setup$")

First I tested the find/egrep to make sure I get the list I want, then I added it as a file list at the end of the tar command.

Hope this helps somewhat.

find . just finds ALL the files under the current directory, though you could specify a subdirectory or a completely different path if you wish.
egrep just allows for multiple grep search strings separated by a pipe (|).
The rest should make sense after that.

3 Answers3