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I am trying to write a CSH script that will look at components of the filename to generate a date/time. The problem is, I have no idea how to extract part of a filename to use it. Here is a sample filename:

nam_218_20140126_1800_001.grb

20140126 is the date portion of the filename and 1800 is the time. I need to extract it and convert it to 2014-01-26_18:00:00 for use in an environment variable. Any hints?

Thanks

Florian Diesch
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WxPilot
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2 Answers2

2
% set filename='nam_218_20140126_1800_001.grb' 
% set datetime=`echo "$filename" | sed -r 's/.*_([0-9]{4})([0-9]{2})([0-9]{2})_([0-9]{2})([0-9]{2}).*/\1-\2-\3_\4:\5:00/'`
% echo $datetime
2014-01-26_18:00:00
Florian Diesch
  • 89,643
0

Use echo and cut. Read man cut, and do something like: 

$ csh
aardvark:~% set zz="nam_218_20140126_1800_001.grb"
aardvark:~% set y=`echo $zz|cut -c9-12`
aardvark:~% echo $y
2014
aardvark:~% set m=`echo $zz| cut -c13-14`
aardvark:~% echo $m
01
aardvark:~% set d=`echo $zz| cut -c15-16`
aardvark:~% echo $d
26
aardvark:~% set H=`echo $zz | cut -c18-19`
aardvark:~% echo $H
18
aardvark:~% set M=`echo $zz | cut -c20-21`
aardvark:~% echo $M
00
aardvark:~% echo "$y-$m-${d}_${H}:${M}:00"
2014-01-26_18:00:00

Not a csh-specific answer.

waltinator
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