How can I determine if a process is running or not and then have a bash script execute some stuff based on that condition?
For example:
if process
abcis running, do thisif it is not running, do that.
A bash script to do something like that would look something like this:
#!/bin/bash
# Check if gedit is running
# -x flag only match processes whose name (or command line if -f is
# specified) exactly match the pattern.
if pgrep -x "gedit" > /dev/null
then
echo "Running"
else
echo "Stopped"
fi
This script is just checking to see if the program "gedit" is running.
Or you can only check if the program is not running like this:
if ! pgrep -x "gedit" > /dev/null
then
echo "Stopped"
fi
Any solution that uses something like ps aux | grep abc or pgrep abc are flawed.
Because you are not checking if a specific process is running, you are checking if there are any processes running that happens to match abc. Any user can easily create and run an executable named abc (or that contains abc somewhere in its name or arguments), causing a false positive for your test. There are various options you can apply to ps, grep and pgrep to narrow the search, but you still won't get a reliable test.
That depends on what you need the test for.
This is what systemd is for. It can start the service automatically and keep track of it, and it can react when it dies.
See How can I check to see if my game server is still running... for other solutions.
In this case, use a lockfile or a lockdir. E.g.
#!/usr/bin/env bash
if ! mkdir /tmp/abc.lock; then
printf "Failed to acquire lock.\n" >&2
exit 1
fi
trap 'rm -rf /tmp/abc.lock' EXIT # remove the lockdir on exit
# rest of script ...
See Bash FAQ 45 for other ways of locking.
This is what I use:
#!/bin/bash
#check if abc is running
if pgrep abc >/dev/null 2>&1
then
# abc is running
else
# abc is not running
fi
In plain English: if 'pgrep' returns 0, the process is running, otherwise it is not.
Related reading:
Bash Scripting :: String Comparisons
Ubuntu Manuals pgrep
I usually have a pidof -x $(basename $0) on my scripts to check if it's already running.
Riffing on @rommel-cid's idea, you can use pidof with the || (||) to run a command if the process does not exist and && to run something if the process does exist, thus creating a quick if/then/else conditional. For example here's one with a running process (my chrome browser, whose process name is "chrome") and one testing for a process that does not exist. I suppressed the standard output using 1>/dev/null so that it doesn't print:
$ (pidof chrome 1>/dev/null && echo "its running? ok, so am i then" ) || echo "it's not running? ok i'll run instea\
d"
its running? ok, so am i then
$ (pidof nosuchprocess 1>/dev/null && echo "its running? ok, so am i then" ) || echo "it's not running? ok i'll run\
instead"
it's not running? ok i'll run instead
$
By pid:
test -d /proc/[pid]
By name:
pgrep -u [user] -x [name] >/dev/null
"-x" means "exact match".
## bash
## function to check if a process is alive and running:
_isRunning() {
ps -o comm= -C "$1" 2>/dev/null | grep -x "$1" >/dev/null 2>&1
}
## example 1: checking if "gedit" is running
if _isRunning gedit; then
echo "gedit is running"
else
echo "gedit is not running"
fi
## example 2: start lxpanel if it is not there
if ! _isRunning lxpanel; then
lxpanel &
fi
## or
_isRunning lxpanel || (lxpanel &)
Note: pgrep -x lxpanel or pidof lxpanel still reports that lxpanel is running even when it is defunct (zombie); so to get alive-and-running process, we need to use ps and grep
None of the "simple" solutions worked for me because the binary I need to check is not installed system-wide, so I have to check with path, which in turn requires using ps -ef | grep approach:
app="$_sdir/Logic 1.2.18 (64-bit)/Logic"
app_pid=`ps -ef | grep "$app" | awk '{print $2}'`
if `ps -p $app_pid > /dev/null`; then
echo "An instance of logic analyzer is appear to be running."
echo "Not starting another instance."
exit 5
else
nohup "$app" &> /dev/null &
fi
First thing that came to my mind for your problem:
ps aux | grep -i abc will show the details of the process if its running. You may match the number of lines or time for which its running and compare with zero or any other manipulation. When you run the above command it will show you atleast one line of output i.e. detail about the process created by thi grep command.. So take care of that.
That should do as a simple hack. Put it in the bash script and see if its helpful.
Using start-stop-daemon:
/sbin/start-stop-daemon --background --make-pidfile --pidfile /tmp/foo.pid -S --startas /usr/bin/program -- arg1 arg2
It works as normal user.
I found that the accepted answer posted by @John Vrbanac did not work for me, and that the answer posted by @geirha doesn't answer the original question.
John Vrbanac's solution didn't work to check if a PHP process was running or not for me, I'm running CentOS 7.
@geirha's answer only makes sure an instance isn't already running before starting another. This was not the original question, the original question was to check if a process is running or not.
Here's what worked for me:
Say my process had the string "Jane" in it's process name. This will find if it's running or not. This works for BASH and PHP scripts.
ps -aux | grep "[J]ane" > /dev/null 2>&1
if [[ "$?" == "0" ]]; then
echo "It's running"
else
echo "It's not running"
fi
#!/bin/bash
while [ true ]; do # Endless loop.
pid=`pgrep -x ${1}` # Get a pid.
if [ -z $pid ]; then # If there is none,
${1} & # Start Param to background.
else
sleep 60 # Else wait.
fi
done