18

I am currently trying to fix my quota system. My problem is that I cannot determine if all files in a directory are owned by the same user. If possible is there a way to list the different owners of files in a directory (recursively).

e.g get-owners-of DIRNAME

dessert
  • 40,956
Jack7076
  • 374

4 Answers4

32

You can use find to print the user (owner) and group and then extract the uniq combinations e.g.

$ sudo find /var -printf '%u:%g\n' | sort -t: -u
_apt:root
avahi-autoipd:avahi-autoipd
clamav:adm
clamav:clamav
colord:colord
daemon:daemon
lightdm:lightdm
lp:lp
man:root
root:adm
root:crontab
root:lp
root:mail
root:mlocate
root:root
root:shadow
root:staff
root:syslog
root:utmp
root:whoopsie
speech-dispatcher:root
statd:nogroup
steeldriver:crontab
steeldriver:lightdm
steeldriver:steeldriver
syslog:adm
systemd-timesync:systemd-timesync
testuser:crontab
steeldriver
  • 142,475
20
stat -c %U *

will list owners of all files.

This can be sorted and duplicates removed by piping it into sort -u:

stat -c %U * | sort -u

As pointed out by steeldriver, this is not recursive. I missed that this was asked for. It can be made recursive by enabling globstar:

shopt -s globstar
stat -c %U **/* | sort -u

Alltogether, steeldriver's answer is probably better and should be the accepted answer here :)

vidarlo
  • 23,497
7

You may find it more efficient to directly search for the files not owned by the user ...

find /directory ! -user username -printf "%u %p\n"
rrauenza
  • 301
4

DIY method via Python:

#!/usr/bin/env python3
import sys,os,pwd
for f in sys.argv[1:]:
    username = pwd.getpwuid(os.stat(f).st_uid).pw_name
    print( ":".join([f,username])  )

This iterates over all filenames listed on command-line, gets UID of the file's owner, and using pwd module gets the username of the owner. After that, filename and username joined for pretty printing and separated via colon. Works as so:

$ ./get_owners.py /etc/* 
/etc/acpi:root
/etc/adduser.conf:root
/etc/alternatives:root
. . .
Sergiy Kolodyazhnyy
  • 107,582