Laurent Expansion on an Annulus
A slightly more general form of the expansion above is the following: Let
be two radii (the expansion around a point corresponds to
), and let
be an annular region around
, and let
be a holomorphic function. Then the Laurent Series

with
is a Laurent expansion of
on
, provided the series converges for all
.
Uniqueness
The coefficients are uniquely determined by:

Proof of Existence and Uniqueness of the Laurent Representation
Uniqueness follows from the Identity Theorem for Laurent Series. To prove existence, choose a radius
such that
and choose
so that
. Let
be arbitrary. "Cut" the annular region
at two points using radii
and
such that the cycle
is represented as the sum of two closed curves
and
in
that are null-homotopic. Choose
and
so that
is encircled by
. By the Cauchy Integral Theorem, we have:

and

since
does not encircle
. Thus, because
, we have:

For
, we have:

The series converges absolutely because
, and we obtain:

Now, consider the integral over the inner circle, which is analogous to the above for
:

Thus, due to
, the series converges, and we obtain:

Thus, it follows that for
:

which proves the existence of the claimed Laurent expansion.